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1、《微机原理及接口技术》（B）答案一、填空1.E0H,-542.1000,3E8H,1111101000B,313030303.50H4.37820H5.由高地址向低地址伸展，字6.NEGAX,；ANDAX,7FFFH7.(1)AX=568AH,AX=5690H(2)AX=0011H,AX=0107H(3)AX=005AH,AX=0090H,AX=0908H8.高速缓冲存储器、内存储器、辅助存储器9.独立的I/O寻址方式、存储器映像的I/O寻址方式，独立的I/O寻址方式。S1二、存储形式：1234S2531323334NB3522NW288FFFBPFFFEFF三、
2、编写程序段1.MOVCL,42.MOVAL,[BX]SHLAX,CLXCHGAL,[BX+3]SHLBL,CLMOV[BX],ALMOVAL,BLMOVAL,1[BX]SHRDH,CLXCHGAL,2[BX]ORAL,DHMOV1[BX],AL3.MOVAH,ALANDAL,0FHCMPAL,0AHJBG1ADDAL,7G1:ADDAL,30HMOVCL,4ANDAH,0F0HSHRAH,CL第4页CMPAH,0AHJBG2ADDAH,7G2:ADDAH,30H四、编写程序。stacksegmentstack‘stack’dw32dup(0)stackendsda
3、tasegmentIBUFDB‘PLEASTINPUTAHEXNUMBER$’,0AH,0DHOBUFDB5,0,5DUP(0)OBUF1DB5DUP(0),‘$’dataendscodesegmentbeginprocfarassumess:stack,cs:code,ds:datapushdssubax,axpushaxmovax,datamovds,axMOVDX,OFFSETIBUFMOVAH,9INT21HMOVDX,OFFSETOBUFMOVAH,10INT21HMOVBL,[OBUF+1]MOVBH,0MOVAX,0MOVCL,4MOVSI,OFFS
4、ETOBUF+2MOVDI,OFFSETOBUF1+4LOP:SHLAX,CLMOVDH,[SI]CMPDH,‘A’JBLOP1SUBDH,7LOP1:SUBDH,30HORAL,DHINCSIDECBXJNZLOPMOVCX,10LOP2:MOVDX,0DIVCXORDL,30HMOV[SI],DLDECDIANDAX,AXJNZLOP2MOVDX,OFFSETOBUF2MOVAH,9INT21Hretbeginendpcodeendsendbegin第4页五、16K×8/2k×8=8,即共需8片存储器芯片。16K=16384=,所以组成16K存储器共需要14根
5、地址线。2K=2048=,即11根作为字选择线，选择存储器芯片片内的单元。14-11=3，3根作为片选择线，选择8片存储器芯片。芯片的11根地址线为,余下的高位地址线为，，，所以译码电路对，，进行译码。译码电路及译码输出线的选址范围如图所示。六、(1)控制电路(2)控制程序：stacksegmentstack‘stack’dw32dup(0)stackendsdatasegmentdataendscodesegmentbeginprocfarassumess:stack,cs:code,ds:datapushdssubax,axpushaxmovax,datamo
6、vds,axAGAIN:MOVDX,280HINAL,DXOUTDX,ALMOVCL,4MOVAH,ALANDAH,0F0HSHRAH,CLCMPAH,‘A’JCADD30ADDAH,7ADD30:ADDAH,30HMOVDL,AH第4页MOVAH,2INT21HANDAL,0FHCMPAL,‘A’JCADD130ADDAL,7ADD130:ADDAL,30HMOVDL,ALMOVAH,2INT21HMOVDL,‘H’MOVAH,2INT21HMOVAH,0BHINT21HCMPAL,0JZAGAINretbeginendpcodeendsendbegin第4页
