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1、微机原理课程设计设计一：从键盘输入十六进制数并显示出二进制值设计二：字符串匹配设计设计三：字符和数据显示的设计设计四：键盘输入小写字母转换成大写字母设计五：计算N！的设计2011-7-6设计一：从键盘输入十六进制数并显示出二进制值实验目的：掌握接收键盘数据的方法，并了解数据显示时须转换为ASCII码的原理。实验内容：将键盘接收到的4位十六进制数据转换为等值的二进制数，再显示在屏幕终端上。流程图：程序源代码：CRLFMACROMOVAH,02HMOVDL,0DHINT21HMOVAH,02HMOVDL,0AHINT21HENDMDATASEGMENTMARKDB?MESSDB'IN
2、PUTTHENUMBER!PressEntertoTransition,PressSpacetoExit!',0DH,0AH,'Input:$'ERRORDB0DH,0AH,'InputError!',0DH,0AH,'$'DATAENDSSTACKSEGMENTSTADW32DUP(?)TOPDW?STACKENDSCODESEGMENTASSUMECS:CODE,DS:DATA,ES:DATA,SS:STACKSTART:MOVAX,DATAMOVDS,AXMOVES,AXMOVSP,TOPHEAD:CRLFMOVMARK,0MOVAH,09HLEADX,MESSINT21H
3、;显示提示输入的信息CALLGETNUM;接收键入数值送DXCMPMARK,01HJEHEADMOVCX,0010H;16位MOVBX,DXTTT:ROLBX,1;循环左移1位MOVDL,BLANDDL,01H;屏蔽掉高7位ADDDL,30HMOVAH,02HINT21H;显示二进制位对应的ASCII字符LOOPTTTJMPHEADFINI:MOVAH,4CHINT21H;返回DOSGETNUMPROCNEAR;子程序,接收键入数值送DXPUSHCXXORDX,DXGGG:MOVAH,01HINT21HCMPAL,0DH;输入为回车,则进行转换JEPPPCMPAL,20H;输入为
4、空格,则退回DOSJEFINICMPAL,30HJBKKKSUBAL,30HCMPAL,0AHJBGETSCMPAL,11HJBKKKSUBAL,07HCMPAL,0FHJBEGETSCMPAL,2AHJBKKKCMPAL,2FHJAKKKSUBAL,20HGETS:MOVCL,04SHLDX,CLXORAH,AHADDDX,AXJMPGGGKKK:MOVAH,09HMOVDX,OFFSETERRORINT21HMOVMARK,01HPPP:PUSHDXCRLFPOPDXPOPCXRETGETNUMENDPCODEENDSENDSTART运行结果设计二：字符串匹配设计实验内容：编
5、写程序实现两个字符串比较。如相同，则显示“MATCH”，否则显示“NOMATCH”。源程序：CRLFMACRO;显示回车MOVDL,0DHMOVAH,02HINT21HMOVAH,02HMOVDL,0AHINT21HENDMDATASEGMENTMESS1DB'MATCH',0DH,0AH,'$'MESS2DB'NOMATCH',0DH,0AH,'$'MESS3DB'INPUTSTRING1!',0DH,0AH,'$'MESS4DB'INPUTSTRING2!',0DH,0AH,'$'MAXLEN1DB100STRING1DB100DUP(?)MAXLEN2DB100STRING
6、2DB100DUP(?)DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATA,ES:DATASTART:MOVAX,DATAMOVDS,AXMOVES,AXMOVAH,09HMOVDX,OFFSETMESS3INT21H;显示输入提示信息1MOVAL,MAXLEN1MOVBX,OFFSETSTRING1MOV[BX],AL;最大字符缓冲MOVAH,0AHMOVDX,OFFSETSTRING1INT21H;接收键入的字符串1CRLFMOVAH,09HMOVDX,OFFSETMESS4INT21H;显示输入提示信息2MOVAL,MAXLEN2MOVBX,O
7、FFSETSTRING2MOV[BX],AL;最大字符缓冲设置MOVAH,0AHMOVDX,OFFSETSTRING2INT21H;接收键入的字符串2CRLFCLDLEASI,STRING1;字符串1的地址送给SIMOVCL,[SI+1];字符串1的字符数送给CXMOVCH,0KKK:LEADI,STRING2;字符串2的地址送给DIMOVDL,[DI+1];字符串2的字符数送给DXMOVDH,0ZJ2:MOVAL,[SI+2];字符串1的第一个字符在字符串2中匹配CMP[DI+
