2、sa*/for(i=0;i#defineN10i
3、ntmain(void){inta[N],i;printf("Enter%dnumbers:",N);for(i=0;i=0;i--)printf("%d",a[i]);printf("");return0;}5数组初始化inta[10]={1,2,3,4,5,6,7,8,9,10};等价于:a[0]=1;a[1]=2;a[2]=3;a[3]=4;……当全部数组元素赋初值时,可不指定数组长度inta[]={1,2,3,4,5,6,7
4、,8,9,10};编译系统根据初值个数确定数组长度初始化元素个数小于数组长度时,数组中剩余元素赋值为0inta[10]={1,2,3,4,5,6};/*initialvalueofais{1,2,3,4,5,6,0,0,0,0}*/6程序:检查数中重复出现的数字(p116)用户输入数后,检查数中是否有出现多于一次的数字Enteranumber:28212Repeateddigit7repdigit.c/*Checksnumbersforrepeateddigits*/#include/*C99only*/#include
5、intmain(void){booldigit_seen[10]={false};intdigit;longn;printf("Enteranumber:");scanf("%ld",&n);while(n>0){digit=n%10;if(digit_seen[digit])break;digit_seen[digit]=true;n/=10;}8if(n>0)printf("Repeateddigit");elseprintf("Norepeateddigit");return0;}9程序举例例读10个整数存入数组,找出其中最大值和最小值步骤:1.
6、输入:for循环输入10个整数2.处理:(a)先令max=min=x[0](b)依次用x[i]和max,min比较(循环)若maxx[i],令min=x[i]3.输出:max和min10#include#defineSIZE10voidmain(){intx[SIZE],i,max,min;printf("Enter10integers:");for(i=0;i7、x[i])min=x[i];}printf("Maximumvalueis%d",max);printf("Minimumvalueis%d",min);}11例用数组求Fibonacci数列前20个数……...11f[19]014523192f[0]f[1]f[2]f[3]f[4]f[5]f[19]35#includevoidmain(){inti;intf[20]={1,1};for(i=2;i<20;i++)f[i]=f[i-2]+f[i-1];for
8、(i=0;i<20;i++){if(i