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1、SolutionstoEnd-of-SectionandChapterReviewProblems455CHAPTER1111.1(a)dfA=c–1=5–1=4(b)dfW=n–c=35–5=30(c)dfT=n–1=35–1=3411.2(a)SSW=SST–SSA=210–60=150(b)(c)(d)11.3(a)SourcedfSSMSFAmonggroups460153.00Withingroups301505Total34210(b)F4,30=2.69(c)Decisionrule:IfF>2.69,rejectH0.(d)Decision:SinceF=3.00isgre
2、aterthanthecriticalbound2.69,rejectH0.11.4(a)dfA=c–1=3–1=2(b)dfW=n–c=21–3=18(c)dfT=n–1=21–1=2011.5SourcedfSSMSFAmonggroups4–1=3(80)(3)=2408080/20=4Withingroups32–4=28560560/28=20Total32–1=31240+560=80011.6(a)Decisionrule:IfFSTAT>2.95,rejectH0.(b)SinceFSTAT=4isgreaterthanthecriticalboundof2.95,reje
3、ctH0.(c)Therearec=4degreesoffreedominthenumeratorandn–c=32–4=28degreesoffreedominthedenominator.Thetabledoesnothave28degreesoffreedominthedenominatorsousethenextlargercriticalvalue,3.90.(d)ToperformtheTukey-Kramerprocedure,thecriticalrangeis=6.166.Copyright©2014PearsonEducation,Inc.SolutionstoEnd-
4、of-SectionandChapterReviewProblems45511.7(a)H0:H1:AtleastonemeanisdifferentA=CapitalRegion,B=GreatLakes,C=Mid-Atlantic,D=NortheastF3,70=2.7355.SinceFSTAT=6.4909>2.7355,rejectH0.ThereisenoughevidenceofadifferenceamongtheCapital,GreatLakes,Mid-Atlantic,andNortheastregionaccountingfirmswithrespecttot
5、hemeannumberofpartners.(b)TheTukey-KramerprocedureshowsthattherearesignificantdifferencesinthemeannumberofpartnersbetweenCapitalandMid-Atlanticregions,andbetweenMid-AtlanticandNortheastregions.11.8(a)H0:H1:Atleastonemeanisdifferent.Copyright©2014PearsonEducation,Inc.SolutionstoEnd-of-SectionandCha
6、pterReviewProblems45511.8(a)cont.Exceloutput:ANOVASourceofVariationSSdfMSFP-valueFcritBetweenGroups1986.4753662.158348.108381.12E-122.866265WithinGroups495.53613.76389Total2481.97539Sincethep-valueisessentiallyzeroandF=48.1084>2.8663,youcanrejectH0.Thereissufficientevidencetoconcludethereisadiffer
7、enceinthemeanstrengthofthefourbrandsoftrashbags.(b)PHStatoutput:TukeyKramerMultipleComparisonsSampleSampleAbsoluteStd.ErrorCriticalGroupMeanSizeComparisonDifferenceofDifferenceRangeResults135.410Group1toGroup20.9
