pp-ps1完整詳解版

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1、PP-ProblemSolving1(PS1)完整詳解版V2.0RevisedHistory由於這是眾人一起完成的,難免會有疏失,希望大家可以一起修正錯誤,讓這份詳解變得更完整!版本增加規則如下:1)修正算式錯誤or提出更好的算法,請把版本小數+1(Ex:V1.0->V1.1)2)增加or補齊題目,請把版本個位數+1(Ex:V2.0->V3.0)版本修正內容(請標題號)作者日期V1.0新增全部詳解(Q1~Q196)pauline_chiou2008-07-01william0625gmanyuma168V1.1UpdateQ36,Q51,Q57,Q139,Q142,

2、Q143larry.tw2008-08-29edas9101V2.05,6,11,13,14,15,17,18,25,28,29,31,37,38,46,47,5iamsmall2008-11-090,55,56,59,61,62,63,67,72,78,80,83,87,91,92,93,97,102,103,107,112,113,114,119,120,121,125,128,129,131,133,150,158,162,168,173,176,177,179,182,187,191,190,193,PracticeTest#1ProblemSolving(

3、196Questions)1.409-!-item-!-187;#058&000306Agrocerystorepurchasedcratesof40orangeseachfor$5.00percrateandthensoldeachorangefor$0.20.Whatwasthestore'sgrossprofitoneachcrateoforanges?(A)$3.00(B)$6.00(C)$8.00(D)$10.00(E)$13.00---------------------------------------------------------------

4、---------------------------------------------------------------------【答案】A【思路】revenue=cost+profit,假設X為thestore'sgrossprofitoneachcrateoforanges0.2x40(soldeachorangefor$0.20)=5(percrate)+X8=5+X,X=3------------------------------------------------------------------------------------------

5、------------------------------------------2.455-!-item-!-187;#058&000316TheproductPoftwoprimenumbersisbetween9and55.Ifoneoftheprimenumbersisgreaterthan2butlessthan6andtheotherisgreaterthan13butlessthan25,thenP=(A)15(B)33(C)34(D)46(E)51---------------------------------------------------

6、---------------------------------------------------------------------------------【答案】E【思路】前提是p是兩個”質數”的乘積oneoftheprimenumbersisgreaterthan2butlessthan6包含3,5theotherisgreaterthan13butlessthan25包含17,19,23p可能為51,57,69,85,95,115(又9

7、-----------------------------------------------------------------------------------3.664-!-item-!-187;#058&000504Acertaintaxicompanycharges$3.10forthefirst[?]ofamileplus$0.40foreachadditionalofamile.Whatwouldthiscompanychargeforataxiridethatwas8mileslong?(A)$15.60(B)$16.00(C)$17.50(D