例谈抽象函数解法(abstract the solution to abstract functions)

例谈抽象函数解法(abstract the solution to abstract functions)

ID:11911616

大小:39.00 KB

页数:15页

时间:2018-07-14

例谈抽象函数解法(abstract the solution to abstract functions)_第1页
例谈抽象函数解法(abstract the solution to abstract functions)_第2页
例谈抽象函数解法(abstract the solution to abstract functions)_第3页
例谈抽象函数解法(abstract the solution to abstract functions)_第4页
例谈抽象函数解法(abstract the solution to abstract functions)_第5页
资源描述:

《例谈抽象函数解法(abstract the solution to abstract functions)》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库

1、例谈抽象函数解法(Abstractthesolutiontoabstractfunctions)Mywell-organizeddocumentAbstract:thesolutiontoabstractfunctionsThefunctionisthehotspotoftheannualcollegeentranceexaminationAndtheapplicationofabstractfunctionisoneofthedifficultpointsAnabstractfunctionisafunctionthatdoesnotgiveaspecificfunctionresolut

2、ionorimageButsomepropertiesoralgorithmsoffunctionsatisfactionaregivenSuchfunctiontestscancomprehensivelyexaminestudents'understandingoffunctionconceptsandtheirabilityofalgebraicreasoningandreasoningItcanalsoexaminestudents'understandingandacceptanceofmathematicalsymbollanguageAndunderstandingofgene

3、ralandspecialrelationshipsSothepropositionalfavorInthelastfewyears,thehighexamquestionisconstantlyappearingBecauseabstractfunctionshavesomeabstractionItsnatureishiddenSostudentsaremoreafraidofabstractfunctionsActually,Alargenumberofabstractfunctionsareabstractedfromthebasicfunctionslearnedinmiddles

4、choolWhentheproblemsolvingStartwiththebackgroundofstudyingabstractfunctionsAccordingtothenatureoftheabstractfunctionByanalogy,guessthatitmightbesomebasicfunctionYoucanalwaysfindawaytodothisThisarticlestartswiththisunderstandingInthispaper,somecommontypesofabstractfunctionsandtheirsolutionsarediscus

5、sed1.LinearfunctionalabstractfunctionsLinearfunctionalabstractfunctionsIt'safunctionthatisabstractedbylinearfunctionsThebasictype:f(x+y)=f(x)+f(y)typicalfunction:f(x)=kxSomedatawhicharefrequentlyused:f(0)=f(0+0)=f(0)+f(0)∴f(0)=0F(0)=f(x-x)=f(x)+f(x)∴f(x)=f(x)-Weknowthatf(x+y)=f(x)+f(y).F(4)=16Let's

6、takefofminus2.F(4)=f(2+2)=f(2)+f(2)=16∴8∴f(2)=f(2)=f(2)=8Weknowthatthisisafunctionoff(x)onRF(2)=1,f(x+y)=f(x)+f(y)Theinequality:f(x)+f(x-2)<3Analysis:itisassumedthatf(x)isanabstractfunctionofy=xAndfofxisamonotoneadditionSolution:3=3f(2)=f(2)+f(2)+f(2)=f(6).∴f(x)+f(x2)<3=f(6)∴x+(x-2)<6∴x<4Example3.T

7、hefunctionf(x)isknowntoanyrealnumberxyIhavef(x+y)=f(x)+f(y).AndwhenxBBB00F(x)>0Fofnegative1isminus2IwantfofxintheintervalTherangeofthetopAnalysis:itisknownfromtheproblemsetFunctionfofxisanabstractfunctionSo

当前文档最多预览五页,下载文档查看全文

此文档下载收益归作者所有

当前文档最多预览五页,下载文档查看全文
温馨提示:
1. 部分包含数学公式或PPT动画的文件,查看预览时可能会显示错乱或异常,文件下载后无此问题,请放心下载。
2. 本文档由用户上传,版权归属用户,天天文库负责整理代发布。如果您对本文档版权有争议请及时联系客服。
3. 下载前请仔细阅读文档内容,确认文档内容符合您的需求后进行下载,若出现内容与标题不符可向本站投诉处理。
4. 下载文档时可能由于网络波动等原因无法下载或下载错误,付费完成后未能成功下载的用户请联系客服处理。