资源描述:
《离子方程式的书写归纳(writing induction of ionic equation)》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、离子方程式的书写归纳(Writinginductionofionicequation)Thewritingofionicequation.Txtthemostpreciousthingintheworldisnotwhatyoucannevergetorwhatyouget,butwhatyouhavegainedandmayloseatanymoment!Loveisalamp,whilefriendshipistheshadow.Whenthelampisoff,youwillfindtheshadow
2、everywhere.Friendiswhocangiveyoustrengthatlast.WritinginductionofionicequationSunXiumin,middleHeilongjiang,Qing'anIonequationandioncoexistencehasbeenahottopicinthecollegeentranceexamination.Itcanbesaidthatitisoftennewandlasting.Forwritingorthetrueorfalseio
3、nequation,someofthestudentsisnotatest,oftenwrong.Infact,suchproblemsarenotdifficult,aslongasthemasterofvarioustypesofionreactionequationwritingmethod,carefulanalysis,youcanaccuratelyanswer,aresummarizedasfollows:First,thereagentdosageisdifferent,theioniceq
4、uationisdifferentAbout1.oftheamountofacidsaltandionequationwritingIngeneral,thenumberofionsisdeterminedaccordingtothechemicalformulaofaninadequateamountofsubstance,andtheionequationofthereactioniswritten.Theratiooftheamountofsubstanceinvolvedintheamountofi
5、onsinthereactionisnotnecessarilyconsistentwiththechemicalformula.Ifthereisnodefinitedosage,itiscorrecttouseanyreactantasanadequateionequation.Example1.Writeoutthecorrespondingionicequation:(1)asufficientamountofNaHSO4solutionismixedwithBa(HCO3)2solution(2)
6、asufficientamountofBa(HCO3)2solutionmixedwithNaHSO4solution(3)addsufficientamountofNaOHsolutiontoCa(HCO3)2solution(4)addsufficientamountofCa(HCO3)2solutiontoNaOHsolutionResolution:(1)bothBa2+andHCO3-areinvolvedinthereaction,andtheNaHSO4isexcessive,soBa2+an
7、dHCO3-appearas1:2intheionicequation,andH+andSO42-aredeterminedasneeded;(2)whentheBa(HCO3)2issufficient,theionicequationdependsontheamountofNaHSO4,andH+andSO42-canonlyappearin1:1,soBa(HCO3)2HCO3-doesnotreactcompletely;(3)Ca2+andHCO3-appearas1:2;(4)according
8、tothequantityofCa(HCO3)2mattermorethanNaOH,thenHCO3-andCa2+canonlyappearin1:1.Answer:(1)2H++SO42-+Ba2++2HCO3-==BaSO4:+2CO2=+2H2O(2)H++SO42-+Ba2++HCO3-==BaSO4:+CO2=+H2OCa2++2HCO3-+2OH-==CaCO3(3):+2H2O+CO32-Ca2