矩量法分析八木天线

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1、如何用基于hallen方程的MoM分析八木天线？clearW$2C47i lamda=1;(

2、`U"vO k=2*pi/lamda;Q_X.rUL0w L1=0.499*lamda;%为什么取0.499而不是0.5ouFYvtFg L2=0.460*lamda;y)!5R3b L3=0.419*l

3、amda;

4、NC*7/} d=0.20*lamda;0dhaAq`k N1=59;YLv'43PL N2=59;F!Q@u N3=59;r^paD2&} dL1=L1/(N1+1);<Fc;_GG dL2=L2/(N2+1);(_)jkI dL3=L3/(N3+1);kDN:ep{/ lz1=-L1/2:dL1:L1/2;
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5、(2:N2+1);4?7W+/~<& lz3=-L3/2:dL3:L3/2;QQ~- lzm3=lz3(2:N3+1);5b[jRj6 M=N1+N2+N3;4K(xd&Q forkm=1:Mm{uxIza   ifkm<=N1x`mNU     A(km).y=-d;{(wHPzq     A(km).z=lzm1(km);<$~mE9a6   elseif(km<=N1+N2)&(km>N1)xJZ>uTN     A(km).y=0;3G~@H>j

6、     A(km).z=lzm2(km-N1);yA(K=?sq   else,JN8f]a^"g     A(km).y=d;@u%_1     A(km).z=lzm3(km-N1-N2);KiOcu=F   end{0^&SI"5`E end!M]I& form=1:Mg[7#w,o   ifm<=N1H0SQ"?     flagm=1;sx51X^d     Vim=0;ZMLg;-T.&4     hm.y=-d;['*8IWg     hm.

7、z=L1/2;njnDW~Snb   elseifm<=N1+N2TdGnf     flagm=2;?
zJOh^     Vim=1;zC:wNz@zK     hm.y=0;fH?ha     hm.z=L2/2;`VL}.h   elseU(;&(W"M     flagm=3;l-$uHHyu*     Vim=0;W$Yc'E;     hm.y=d;%9#gB     hm.z=L3/2;~

8、AwN[   endhw~a:kD   

9、forn=1:M*cg(?yg     ifn<=N1

10、2y"5     endW];EKj,3W     i

11、fm==nxDO7A5       Rhmn=sqrt((hm.z-A(n).z)^2+a^2);www`=)A;       Fmn=(1/(2*pi))*log(dL/a)-j*k*dL/(4*pi);kDz>r#%       Fhmn=exp(-j*k*Rhmn)/(4*pi*Rhmn)*dL;r++i=SQax     elseGr(

12、Ra.       ifflagm==flagnELh3^         Rhmn=sqrt((hm.z-A(n).z)^2+a^2

13、);nD,{3B#         Rmn=sqrt((A(m).z-A(n).z)^2+a^2);9

14、S`ub'       elseg3?U#7i         Rhmn=sqrt((hm.y-A(n).y)^2+(hm.z-A(n).z)^2);C/v}^#cLD         Rmn=sqrt((A(m).y-A(n).y)^2+(A(m).z-A(n).z)^2);hWcTI
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