工程力学与建筑结构离线作业(1)

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1、浙江大学远程教育学院《工程力学与建筑结构》课程作业姓名：学号：年级：学习中心：—————————————————————————————一、作图题1．用力的平行四边形法则求以下两力的合力。FF=F1+F2FA2．试画出如图所示小球的受力图GFBOloanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersonsorinstitutions.Reviewfindingsa

2、ndreviewcomments,accordingtotheBank'scredit173.分别画出图中两个物体系中各杆件的受力图和各物体系整体的受力图。（注意有二力杆时的画法。）FDFaxFcxFcyFayDD两力杆件三力交汇CFAloanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersonsorinstitutions.Reviewfindingsandrev

3、iewcomments,accordingtotheBank'scredit17(b)FFayFaxFb4.杆件受力如图所示，试求杆内的轴力并作出轴力图。（1）1截面：FN1=P4+P2-P1-P3=25KN(拉)2截面：FN2=P2+P4-P3=45KN(拉)3截面：FN3=P4-P3=-15KN（压）loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersons

4、orinstitutions.Reviewfindingsandreviewcomments,accordingtotheBank'scredit174截面：FN4=P4=10KN(拉)（2）取左侧为研究对象1截面：FN1=P1=20KN(拉)2截面：FN2=P1+P2=40KN(拉)3截面：FN3=P1+P2-P3=10KN(拉)loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecision

5、powerofpersonsorinstitutions.Reviewfindingsandreviewcomments,accordingtotheBank'scredit175．画出图示各梁的剪力图和弯矩图。a）∑Fx=0得Fax=0∑Fy=0得Fay=0∑Mo=0得MA=P×L÷2-P×L=-P×L÷2（顺时针）b）∑Fx=0得FAx=0∑Fy=0得FAy+FBy=1结合下面的FAy=0.75∑Mo=0得MA=FBy×2-1×1×1÷2=0可推出FBy=0.25loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordanc

6、ewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersonsorinstitutions.Reviewfindingsandreviewcomments,accordingtotheBank'scredit176．试作图示刚架的M、Q、N图。M图Q图N图4m4m2m2m2m60KN2m20KN2m40KN.m80KN.m2m4m7．试判断图示杆架中的零杆。一．计算题1.杆AO和杆BO相互以铰O相连接，两杆的另一端均用铰连接在墙上。铰O处挂一个重物Q＝50kN，如图所示。试用解析法求杆AO

7、和杆BO所受的力．loanapprovalandpostcreditapprovalofficer/atalllevelsinaccordancewithcreditapprovalrules,licensingandeventualexerciseofcreditdecisionpowerofpersonsorinstitutions.Reviewfindingsandreviewcomments,acco