4、f(“x=%d,y=%d”,&x,&y);printf(“x=%d,y=%d”,x,y);}5.用指针作函数参数,对输入的两个整数按大小顺序输出。swap(int*p1,*p2){int*p;正确:intt;*p=*p1;*p1=*p2;*p2=*p;t=*p1;*p1=*p2;*p2=t;}main(){inta,b;int*q1,*q2;scanf("%d,%d",&a,&b);&q1=a,&q2=b;q1=&a,q2=&b;if(a
5、p(q1,q2);printf("%d,%d",q1,q2);printf("%d,%d",*q1,*q2);}6.求100~300间能被3整除的数的和。main(){intn;sum;6for(n=100;n<=300;n++){if(n%3=0)sum=sum*n;}printf(“%ld”,sum);}7.实现华氏温度转换为摄氏温度,公式为:c=*(f-32),要求输出结果取2位小数。main(){intc,f ;printf("Pleaseenterf:");scanf("%
6、f",&f);c=5/9*(f-32);printf("f=%f,c=%f",c,f);}8.下面程序的功能是计算n!。main(){inti,n;ints;printf("Pleaseentern:");scanf("%d",n);for(i=1;i<=n;i++);s=*i;printf("%d!=%d",i,s);}9、求一个4×4矩阵的对角线元素之和main(){inta[4][4],sum=0;inti,j;printf(“Enterdata:”);for(i=0;i<=4;I++)f
7、or(j=0,j<=4;j++)scanf(“%d”,&a[i][j]);for(i=0;i<4;I++)for(j=0;j<4;j++)6sum=sum+a[i][j];printf(“sum=%5d”,sum);}10.编程计算下面分段函数,输入x,输出ymain(){intx,y;printf(“Inputx:”);scanf(“%d”,x);if(x<0)y=x-1;elseif(x>=0
8、
9、x<=10)y=2x-1;elsey=3x-1;printf(“y=%d”,&y);}1
10、1.求表达式的值#include#includeintfun(intx,inty);main(){inta,b;floatf;scanf(“%d,%d”,a,b);if(ab>0){f=fun(a,b);printf("Theresultis:%d",&f)}elseprintf(“error!”);}fun(x,y){floatresult;result=sqrt(a+b);return;}12、通过函数调用,求两个数之差6su