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时间:2018-11-30
《《钢结构原理与设计第二版》中国建筑工业出版社夏志斌-部分课后答案》由会员上传分享,免费在线阅读,更多相关内容在应用文档-天天文库。
1、4.1解:12NNN1.23151.4315420kNGGKQQK33W2焊缝质量为三级,用引弧板施焊。查表得E43焊条的f185N/mm,tQ235钢的2f215N/mm。3N42010t11.35mmWbf200185t故取t12mm。4.2解:NNN1.20.2N1.40.8N1.36NGGKQQKkkkW2焊缝质量为二级,f215N/mm未用引弧板施焊tl400212376mmWWNWf,Nflt1.36NttWkltWWflt21537612tWN713.3kNk1.3
2、61.364.4解:1)焊脚尺寸hfhf11.5tmax1.5104.74mm背部尺寸hf11.2tmin1.289.6mmhf21.5tmax1.5104.74mm趾部尺寸ht1~281~26~7mmf2min为方便备料,取hhh6mm,满足上述要求。f1f2f2)轴心力N的设计值NNN1.20.11801.40.9180248.4kNGGKQQK按角钢背与趾部侧面角焊缝内力分配系数可知:等边角钢内力分配系数ee120.30.7bb对角钢趾部取力矩平衡得:NbNe
3、12e2NN0.3N0.3248.474.52kN1bNNN0.7N0.7248.4173.88kN213)焊缝长度。当构件截面为一只角钢时,考虑角钢与节点板单面连接所引起的偏心影响,Wf应乘以折减系数0.85。t3N74.52101角钢趾:l130mm8h48mmW1Wf0.7h0.85f0.760.85160ff取l1140mm(1302hf142mm,取10mm的整数倍)3N173.88102角钢背:l304mm60h360mmW2Wf0.7h0.85f0.760.85160ff取l2
4、320mm(3042hf316mm,取10mm的整数)4.5解:腹板受到轴心拉力N作用kNNN1.20.24401.40.8440598.4kNGGKQQK焊脚尺寸hfhf1.5tmax5.6mm,hftmin(1~2)8~9mm3N598.410取hf6mm时,lWW445.2mm60hf360mm20.7hf20.76160ff不可行;取hf7mm时,lw381.6mm,lw60hf420mm可行,l381.62h395.6mm,取l400mmf取hf9mm时,lw296.8mm
5、,lw60hf540mm可行,l296.82h314.8mm,取l320mmf故最小的焊脚尺寸可取7mm,钢板搭接长度为400mm最大的焊脚尺寸可取9mm,钢板搭接长度为320mm4.7解:(1)直接计算法MNl500.210kNm6M10101488.12N/mmf220.7hl60.7h2406hfWff3N5010297.62N/mmf0.7hl0.7h240hfWff2f2Wffff221488.1297.61601.22hhff解得:h7.8
6、5mmf1.5t1.5186.36mm采用maxh8mm,可ft1~28~9mmmin(2)试算法1.5t1.5186.36mmmaxhft1~28~9mmmin取hf8mm2Ahl0.7hl0.782401344mmWeWfW12123Whl0.7824053760mmWeW666M10102186.0N/mmf220.7hl60.782406fW3N5010237.2N/mmf0.7hl0.78240fW22f218622W2f3
7、7.2156.9N/mmff160N/mm,可f1.22故hf8mm4.8解:R1.225%R1.475%R405kNkkl300mml801070mmh取焊脚尺寸h6mmh0.7h4.2mmfef(1)几何关系水平焊缝计算长度llh70664mmWhhf全部焊缝计算长度ll2l300264428mmWWh全部焊缝有效截面AhlWeWlhlWh2eWh22h6.46.42e形心位置x0.96cmAh42.8We略去3h项e3232hell0.4230304Ix
8、2helWh20.
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