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时间:2018-12-05
《双闭环直流调速系统matlab仿真》由会员上传分享,免费在线阅读,更多相关内容在学术论文-天天文库。
1、双闭环直流调速系统MATLAB仿真一、实验原理W⑽一、实验内容基本数据如h直流电动机:220V,136A,1460r/min.Ce=0.132Vmin/r.允许过载倍数为1.5;晶闸管装置放大系数:Ks=40;Ts=O.0017s;电枢回路总电阻:R=O.5Q;吋间常数:T,=0.035,rm=0.185;电流反馈系数:/?=0.05V/A;电流反馈滤波时间常数:7;=0.0025;电流反馈系数:^=0.05V/A;转速反馈系数a=0.007vmin/r转速反馈滤波时间常数:7b/7=0.0k设计要求:设计电流调节器,要求电流无静差
2、,电流超调量<rfS5%。转速无静差,空载起动到额定负载转速时转速超调量R10%。并绘制双闭环调速系统的动态结构图。Trjr«s1erFcr^A0015*1分D分cAConstantUnivtrsjlBridgeBfoohUaUt>0ui2Ucalpha60OCVoltjg«SourceConstantlConrtjnt2Gdin3Dtrivjtivt□Soop®Snvtch130ASRACRSatufJtionlConstinMSubfyrttmdu/dtADRSaturation2SaturationSwitch1PIConit
3、jnt3-180Ojin24、nicsSeriesRLCbranchSimpowersystem/ElenemtsC=infL=0纯电阻VIotageMeasurementSimpowersystem/MeasurementsCurrentMeasurementSimpowersystem/MeasurementsMultimeterSimpowersystem/MeasurementsTConnectorSimpowersystem/connectorsScopeSimulink/sinksMuxSimulink/SigiialRoutingDemuxSimu5、link/SignalRoutingPulseGeneratorSimulink/SourcesstepSimulink/sources‘0’‘0’‘10’‘0’IntegratorSimulink/continuous/‘0’‘1(T‘-10’TransferFenSimulink/continuous/gainSimulink/mathoperationssumSimulink/mathoperations+-KTKptiki=Kp/ti0.250.50670.0316.890.51.0130.0334.7712.0270.036、67.567计算电流环设计成典型一型系统选用PI调节器Ti=TL,Xp=KTt.R取KT=0.5转速环设计成典型二型系统h=5,Trn=h(2TZi+T(>ll)=0.087Kn=Kn(h+V)/3CeTmIhaRT^n=11.7取11.7,11.7/0.0874X
4、nicsSeriesRLCbranchSimpowersystem/ElenemtsC=infL=0纯电阻VIotageMeasurementSimpowersystem/MeasurementsCurrentMeasurementSimpowersystem/MeasurementsMultimeterSimpowersystem/MeasurementsTConnectorSimpowersystem/connectorsScopeSimulink/sinksMuxSimulink/SigiialRoutingDemuxSimu
5、link/SignalRoutingPulseGeneratorSimulink/SourcesstepSimulink/sources‘0’‘0’‘10’‘0’IntegratorSimulink/continuous/‘0’‘1(T‘-10’TransferFenSimulink/continuous/gainSimulink/mathoperationssumSimulink/mathoperations+-KTKptiki=Kp/ti0.250.50670.0316.890.51.0130.0334.7712.0270.03
6、67.567计算电流环设计成典型一型系统选用PI调节器Ti=TL,Xp=KTt.R取KT=0.5转速环设计成典型二型系统h=5,Trn=h(2TZi+T(>ll)=0.087Kn=Kn(h+V)/3CeTmIhaRT^n=11.7取11.7,11.7/0.0874X
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