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1、5.1顺序分支循环5.2(AX)=5400H(BL)=06H(DX)=2106H5.3D5.4C5.5B5.6D5.7C5.80FFH05.9C5.10略5.11B5.12A5.1323H01H56H04H00H5.14将BUF里的小写字母转换成大写字母5.15略5.16（1）完成85274AH与938765H的加法功能（2）不能。INC对CF无影响，而ADD有影响（3）MOVSI，OFFSETDATA1（4）置CF为零。若CF初始为1，则在第一次执行ADC指令时会产生不正确的结果。5．17（编程题为参考答案，下同）DATASEGMENTDAT
2、A1DB？DATA2DB？DATAENDSCODESEGMENTASSUMECS：CODE，DS：DATABEGIN：MOVAX，DATAMOVDS，AXMOVDX，DATA1；高位送DXMOVAX，DATA2；低位送AXSHLAX,1;RCLDX,1;MOVAH,4CHINT21HCODEENDSENDBEGIN5.18DATASEGMENTDATASDB‘PLEASTINPUT：’,0DH,0AH,‘$’DATAENDSCODESEGMENTASSUMECS:CODE，DS:DATABEGIN:MOVAX,DATAMOVDS,AXMOVAH
3、,9HINT21H;输出“PLEASEINPUT：”MOVAH，1INT21H;用户输入MOVDL,ALSUBDL,20HMOVAH,2INT21H;显示输出MOVAH，4CHINT21HCODEENDSENDBEGIN5.19DATASEGMENTARRAYDB20DUP（？）；原数列PLUSDB20DUP（0）；存放正数NEGADB20DUP（0）；存放负数PLUS_NDB0；指示正数个数NEGA_NDB0；指示负数个数TIMEDB20DATAENDSCODESEGMENTASSUMECS:CODE，DS:DATABEGIN:MOVAX,D
4、ATAMOVDS,AXLEASI,ARRAYLEABX,PLUSLEADI,NEGAMOVCX,TIMECLC；以上为初始化LOOP1:MOVAL,[SI]CMPAL,0INCSIJADAYUJBXIAOLOOPLOOP1；等于零处理JMPSHOWDAYU:MOV[BX],AL；大于零的处理INCBXINCPLUS_NLOOPLOOP1JMPSHOWXIAOYU:MOV[DI],AL；小于零的处理INCDIINCNEGA_NLOOPLOOP1SHOW:MOVDL,PLUS_N；屏幕显示输出MOVAH,2INT21HMOVDL,NEGA_NMOV
5、AH,2INT21HMOVAH,4CHINT21HCODEENDSENDBEGIN5.20STACKSEGMENTPARASTACKDB10HDUP(0)STACKENDSCODESEGMENTASSUMECS:CODE,SS:STACKBEGIN:PUSHF；标志位入压入栈POPAX；出栈到AXEXCHANGEAH,AL；高低位互换PUSHAX；AX压入栈POPF；弹出到标志寄存器CODEENDSENDBEGIN5.21DATASEGMENTSTRDB‘INPUT1OR0’，0DH，0AH，‘$’BUFFDB20DUP(0)LENDW10DA
6、TAENDSCODESEGMENTASSUMECS:CODE,DS:DATABEGIN:MOVAX,DATAMOVDS,AXMOVDX,OFFSETSTRMOVAH,09HINT21HMOVBH,48；零的ASCII码MOVBL,65；A的ASCII码LEASI,BUFFMOVCX,LENMOVAH,1HINT21HCMPDL,1JZACMPDL,2JZBJMPEND0；输入非1非2即结束程序A:MOV[SI],BHINCSIMOV[SI],BLINTSIMOVDL,BHMOVAH,2INT21HMOVDL,BLMOVAH,2INT21HINC
7、BHINCBLLOOPAJMPEND0B:MOV[SI],BLINCSIMOV[SI],BHINCSIMOVDL,BLMOVAH,2INT21HMOVDL,BHMOVAH,2INT21HINCBLINTBHLOOPBEND0:MOVAH,4CHINT21HCODEENDSENDBEGIN5.22DATASEGMENTXDB?YDB?ZDB?SUMDB0DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATABEGIN:MOVAX,DATAMOVDS,AXMOVAX,XADDAX,YCMPAX,200MOVAX,XJGSU
8、B0；判断ADDAX,ZJMPEND0SUB0:SUBAX,ZEND0:MOVSUMAXMOVAH,4CHINT21HCODEENDSENDBEGIN
