BERKELY-analogue circuit design

BERKELY-analogue circuit design

ID:40049555

大小:2.35 MB

页数:463页

时间:2019-07-18

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1、EECS140ANALOGCIRCUITDESIGNINTRODUCTIONUniversityofCaliforniaBerkeleyCollegeofEngineeringDepartmentofElectricalEngineeringandComputerScienceRobertW.BrodersenEECS140AnalogCircuitDesignROBERTW.BRODERSENLECTURE1EECS140ANALOGCIRCUITDESIGNINTRODUCTIONI-1EECS140ANALOGINTEGRATEDC

2、IRCUITSRobertW.Brodersen,2-1779,402CoryHall,rb@eecs.berkeley.eduThiscoursewillfocusonthedesignofMOSanalogintegratedcircuitswithextensiveuseofSpiceforthesimulations.Inaddition,someapplicationsofanalogintegratedcircuitswillbecoveredwhichwillincludeRFamplificationanddis-cret

3、eandcontinuoustimefiltering.ThoughthefocuswillbeonMOSimplementations,comparisonwithbipolarcircuitswillbegiven.RequiredTextAnalysisandDesignofAnalogIntegratedCircuits,4thEdition,P.R.Gray,P.Hurst,S.LewisandR.G.Meyer,JohnWileyandSons,2001SupplementalTextsB.Razavi,DesignofAna

4、logCMOSIntegratedCircuits,McGraw-Hill,2001.ThomasLee,TheDesignofCMOSRadioFrequencyIntegratedCircuits,CambridgeUniversityPress,1998TheSPICEBook,AndreVladimirescu,JohnWileyandSons,1994PrerequisitesEECS105:MicroelectronicDevicesandCircuitsROBERTW.BRODERSENLECTURE1EECS140ANAL

5、OGCIRCUITDESIGNINTRODUCTIONICDesignCourseStructureatBerkeleyI-2EE40EE105EE140EE142EE141Linear/AnalogNon-LinearDigitalLinearDesignSensors,InterfaceDigitalTransducersCircuitsProcessingAmplifiers,Filters,A/D&D/A’sROBERTW.BRODERSENLECTURE1EECS140ANALOGCIRCUITDESIGNLECTURESONM

6、OSDEVICEMODELSUniversityofCaliforniaBerkeleyCollegeofEngineeringDepartmentofElectricalEngineeringandComputerScienceRobertW.BrodersenEECS140AnalogCircuitDesignLecturesonMOSDEVICEMODELSROBERTW.BRODERSENLECTURE2EECS140ANALOGCIRCUITDESIGNLECTURESONMOSDEVICEMODELSM-1AssumedKno

7、wledgea)KCL,KVL-KirchoffLawsb)Voltage,CurrentDividersc)Thevenin,NortonEquivalentsd)2-PortEquivalentse)Phasors,FrequencyResponseROBERTW.BRODERSENLECTURE2EECS140ANALOGCIRCUITDESIGNLECTURESONMOSDEVICEMODELS2-PortEquivalentCircuitM-2RL®¥(Voltagein-Voltageout)niniinioutRin=---

8、--iini®0out++RsRoutnout+nin+nRout=-------outiVs--outRS==nin0Rinan×ninRL--noutAn=-------ninRL®¥ii

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