独木桥问题多线程--java编程

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1、publicclassPedestrianimplementsRunnable{staticintan,bn;staticintcount;booleanas=false,bs=false;publicstaticvoidmain(String[]args){Pedestrianp=newPedestrian();}publicPedestrian(){Scannerinputa=newScanner(System.in);System.out.println("请输入在a方向的行人数目：");an=inputa.nextInt();Sca

2、nnerinputb=newScanner(System.in);System.out.println("请输入在b方向的行人数目：");bn=inputb.nextInt();count=an+bn;while(count>0){thread1a=newthread1(this,"a");a.start();thread1b=newthread1(this,"b");b.start();}}classthread1extendsThread{publicthread1(Runnabler,Stringname){super(r,name)

3、;}}publicsynchronizedvoidrun(){thread1t=(thread1)Thread.currentThread();if(t.getName().equalsIgnoreCase("a")&&an>0&&bs==false){as=true;inti=(int)(Math.random()*100%an);if(i

4、em.out.println("a方向上新增人数："+n+"现要过桥人数为："+(an+n));an=an+n;if(an==0){System.out.println("a方向上的人已全过桥！");}as=false;}if(t.getName().equalsIgnoreCase("b")&&bn>0&&as==false){bs=true;intj=(int)(Math.random()*100%bn);if(j

5、+bn);intm;m=(int)(Math.random()*2);System.out.println("b方向上新增人数："+m+"现要过桥人数为："+(bn+m));bn=bn+m;if(bn==0){System.out.println("b方向上的已全过桥！");}bs=false;}count=an+bn;}}