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1、第一题：源程序：;从屏幕上输入大写字母，转换为小写字母并输出（生成.com文件）;要求：程序具有可读性、容错性homework1segmentparaassumecs:homework1,ss:homework1,ds:homework1org0100hmainprocfarleadx,str1movah,09hint21h;显示输入提示main0:movah,01h;输入字符int21hcmpal,41h;输入判断jbmain1cmpal,5ahjamain1leadx,str4;显示输入成功提示movah,09hint21haddal,20h;大写字母的ASCII-->小写
2、字母的ASCIIpushaxleadx,str2;显示输出提示movah,09hint21hpopaxmovdl,almovah,02h;显示小写字母int21hmovax,4c00h;退出OSint21hmain1:;错误提示leadx,str3movah,09hint21hjmpmain0mainendpstr1db0dh,0ah,'Pleaseinputabigcasecharacter:$'str2db0dh,0ah,'Theconvertedresultis:$'str3db0dh,0ah,'Thereisainputerror,pleaseinputagain!$'
3、str4db0dh,0ah,'Thecharacteryouhaveinputedisright!$'homework1endsendmain运行结果：第二题：源程序：;编写一子程序asc2bin，将ASCII转换为二进制数;要求：输入参数：AL中存放需要转换的ASCII;输出参数：AL中存放转换后的二进制数并返回datasegmentparavardb31h,39h,46hbufdb3dup(0)dataendsss_segsegmentstackdb100dup(0)ss_segendscodesegmentparaassumecs:code,ss:ss_seg,ds:da
4、tamainprocfarmovax,data;数据段赋值movds,axmovbx,0moval,var[bx]callasc2binmovbuf[bx],alincbxmoval,var[bx]callasc2binmovbuf[bx],alincbxmoval,var[bx]callasc2binmovbuf[bx],almovax,4c00hint21h;编写一个把ASCII转换为二进制数的子程序;入口参数：AL中存放需要转换的ASCII;出口参数：AL中存放转换后的二进制数并返回asc2binprocsubal,30hcmpal,09hjbemain1subal,07
5、hmain1:retasc2binendpmainendpcodeendsendmain运行结果：第三题：源程序：;内存中存放8个16位有符号数，求8个数值之和，并将结果存放在内存变量SUM中;注：程序中应用到字扩展为双字的指令CWDdatasegmentparabufdw12000,-14586,28965,-31596,14896,25478,32145,-26987sumdd0dataendsss_segsegmentstackdw100dup(0)ss_segendscodesegmentparaassumecs:code,ss:ss_seg,ds:datamainpr
6、ocfarmovax,data;数据段赋值movds,axmovcx,8;设置循环次数movbx,0circle:movax,buf[bx]cwd;ax-->dx,axaddwordptrsum,axadcwordptrsum+2,dxaddbx,2loopcirclemovax,4c00hint21hmainendpcodeendsendmain运行结果：第四题：源程序：;内存中存放8个8位有符号数，请按从大到小顺序排列datasegmentparabufdb-128,127,-112,123,-109,112,0,64countequ($-buf)dataendsss_se
7、gsegmentstackdb100dup(0)ss_segendscodesegmentparaassumecs:code,ss:ss_seg,ds:datamainprocfarmovax,data;对数据段赋值movds,axmovcx,count-1;定义最多的外循环次数circle2:;外循环movbx,0movdx,0;设置标志pushcx;保存外循环的CXcircle1:;内循环moval,buf[bx]cmpal,buf[bx+1]jgemain1xchgal,buf[bx+
