资源描述：
《微机原理复习题()（review of principles of microcomputer ()）》由会员上传分享，免费在线阅读，更多相关内容在教育资源-天天文库。
1、微机原理复习题(2010)（Reviewofprinciplesofmicrocomputer(2010)）Microcomputerprinciple,applicationandcontrolreviewFirst,themultiple-choicequestion1,amemoryunittothebaseaddressis2000H,offsetis0C800H,thenthephysicaladdressoftheunit(for).A.20000H,B.,2C800H,C.,0C8000H,D.,0CA000H2,thefo
2、llowingfourinstructions,thewronginstructionis().A.,MOV,AH,64H,B.,MOV,BL,8AH,C.,MOV,8F,AL,D.,MOV,[100H],AL3,8K*8bitEPROM,itsaddresslineanddatalinenumberare().A.8,8,B.13,8,C.12,8,D.13,4Thereare(C)kindsofworkin4and8253.A.4kindsofB.,5kindsofC.,6kindsofD.,8kinds5,whenthe8253ch
3、ipiswrittentothecontrolword36H,thechannelusedis().A.1channelB.,0channelC.,2channelD.,3channelsarenotrequired6,knownparallelinterfacechip8255Ainthemicrocomputerapplicationsystemcontrolportaddressis203H,anditsCportaddress202H,thenitsBportaddressis().A.200H,B.,201H,C.,205H,D
4、.,207H7,asystemrequiresthattheoutputoftheD/Aconverterbe0to+5.12V,witharesolutionof5mV,andthenumberofbitsoftheD/AconvertertobeselectedshouldbeatleastCA.8bit,B.10bit,C.12bit,D.16bit8,thedecimalnumbercorrespondingtothebinarycodeis-97(B)A.10011110B,B.,10011111B,C.,11100000B,D
5、.,11100001B9unsignedbinarynumber11010111Bcorrespondstothedecimalnumberis()A.653B.327C.215D.12510,whenthearithmeticoperation,iftheresultsoftheoverflow,then()A.CF=1,B.,DF=1,C.,OF=1,D.,ZF=111.Thewronginstructioninthefollowingfourinstructionsis(D).A.,MOV,AX,2000H,B.,MOV,BX,[2
6、000H],C.,MOV,DS,AX,D.,MOV,DS,2000H12、inthePC/ATbus,whentheI/Oreadoperationisperformed,thevalidsignalis()A./IOR,B.,/IOW,C.,/MEMR,D.,/MEMW13and8086microaddressbus20,intherealaddressmode,themicroprocessoraddressingrangeof(A)A.00000H---0FFFFFH,B.,00000H---0AFFFFH,C.,00000H---
7、1FFFFH,D.,0000H---0FFFFHTheinterrupttypenumberof14and8086CPUis()A.,0---7H,B.,0---FH,C.,20---27H,D.,00---0FFH15,8253ofthetimercounter,the0channelissetto16bitcountmode,theinitialnumberofwriteis:BA.1times,B.2times,C.4times,D.6times16,a12bitunipolarA/Dconverterwitharangeof0--
8、-+10V,witharesolutionof(B)Delta=1/(2N-1)(Ndigits)A.,1.22mv,B.,2.44mv,C.,5mv,D.,10mV17,INTEL8088m
