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大小:982.50 KB
页数:75页
时间:2019-12-03
《高中数学第二章小结与复习课件新人教必修》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、第二章复习Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientP
2、rofile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluati
3、ononly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0
4、.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.Create
5、dwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.一、本章知识框架Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright200
6、4-2011AsposePtyLtd.二、本章的主要概念1.映射2.函数3.函数的单调性4.反函数5.分数指数幂与根式6.指数函数7.对数8.对数函数Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.三、本章的主要方法Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011Aspose
7、PtyLtd.三、本章的主要方法1.相同函数的判断方法:Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.三、本章的主要方法1.相同函数的判断方法:①定义域相同;Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.三、本章的主要方法1.相同函数的判断方法:
8、①定义域相同;②值域相同;Evaluationonly.CreatedwithAspose.S
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