江苏省苏州市2017届中考数学二模试题

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1、江苏省苏州市2017届中考数学二模试题9．如图△ABC中，∠C=90°，AC=4，BC=3，将△ABC绕点A逆时针旋转，使点C落在线段AB上的点E处，点B落在点D处，则B、D两点间的距离为（）A．2B．C．3D．2110．如图点A、B在反比例函数y=（k＞0，x＞0）图象上，BC∥x轴，交y轴于点C，动点P从坐标原点O出发，沿O→A→B→C（图中“→”所示路线）匀速运动，终点为C，过P作PM⊥x轴，垂足为M．设三角形OMP的面积为S，P点运动时间为t，则S关于x的函数图象大致为A．B．C．D．2三、解答题：本大题共11小题，共76分．把解答过程写在答题卡相应位置上，解答时应写出必要的

2、计算过程、推演步骤或文字说明，作图时用2B铅笔或黑色墨水签字笔．2019．（本题满分5分）计算：(3)2(5)．x1220．（本题满分5分）解不等式组：2x2x1345参考答案一、选择题（每小题3分，共30分）题号12345678910答案CBCAADBDBA二、选择题（每小题3分，共24分）7211．(a+3)(a-3)12．4.51×1013．814．901015．6016．17．43一418．①、②、③3三、解答题（共11大题，共76分）19．（本题共5分）解：原式=32+1·································

3、·············································3分=2···························································································5分20．(本题共5分)解：由①式得：x>3．·············································································2分由②式得：x4．············································

4、·······························4分∴不等式组的解集为：3x4．·················································5分21．(本题共6分)xx解：原式=·············································································1分2x1x1xx1=······································································2分(x1)(x1)x1=

5、······················································································4分x11当x=21时，原式=····································································5分22=．····················································································6分222．（本题满分6分）解：设骑电瓶车学生的速度为xkm/h，汽

6、车的速度为2xkm/h，可得：··········1分101020＝＋，x2x60·········································6······································3分解得x＝15，······················································································4分经检验，x＝15是原方程的解，······························································

7、5分2x＝2×15＝30.答：骑车学生的速度和汽车的速度分别是15km/h，30km/h.·························6分23．（本题共8分）(1)证明：∵四边形ABCD为平行四边形∴AD∥BC，AB∥CD，AB=CD，·····································································1分∴∠B+∠C=180°,∠AEB=∠DAE，················