海上货物运输评估项目“货物积载与系固――货物单元的积载和系固”答题卷.doc

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1、题卡号：编码：题目：校核舱面货物单元的系索强度评估时间：40分钟评估方式：实操评估项目“货物积载与系固——货物单元的积载和系固”答题卷姓名：学号：成绩：一、系固方案核查计算用表有关船舶资料表表-1船长L(m)航速V(节)船宽B(m)GM(m)B/GM有关货物资料表表-2垂向货位纵向货位/L(距船尾)货物质量(t)货物尺度横向力臂LZ(m)系固点高度h(m)货重心距支点横距b1(m)摩擦系数μ长(m)宽(m)高(m)(1)(2)(3)(4)(5)=(4)/2(6)(7)=(3)/2(8)有关系索资料表表-3系索编号横

2、向系索纵向系索左/右系固角MSLCS力臂lfCS×fCS×l前/后系固角MSLCSfCS×f(9)(10)(11)=(10)/1.5(12)*(13)(11)×(13)(11)×(12)(14)(15)(16)=(15)/1.5(17)(16)×(17)1左前2左(18)(19)(20)合计(左)合计前(右)后注*(12)=((3)+(6)/tg(9))×sin(9)甲板货物单元的风压力和波溅力计算表表-4风压力波溅力横向风压力纵向风压力横向波溅力纵向波溅力(21)=(2)×(4)(22)=(3)×(4)(23)=

3、2×(2)(24)=2×(3)货物单元的加速度计算表表-5基本加速度K1K2修正后的加速度m(g-az)a0ya0xa0zayaxaz(25)(26)(27)(28)(29)(30)=(25)×(28)×(29)(31)=(26)×(28)(32)=(27)×(28)(33)=(1)×(9.81－(32))货物单元的运动情况核查表表-6横向移动核查横向倾覆核查纵向移动核查横向移动力Fy横向约束力[Fy]合格否?Fy<[Fy]?横向倾覆力矩My横向约束力矩[My]合格否?My<[My]纵向移动力Fx纵向约束力[Fx]

4、合格否?Fx<[Fx]?(34)=(1)×(30)+(21)+(23)(35)=9.81×(1)×(8)+(18)(34)<(35)?(36)=(34)×(5)(37)=9.81×(1)×(7)+(19)(36)<(37)?(38)=(1)×(31)+(22)+(24)(39)=(33)×(8)+(20)(38)<(39)?二、附表基本加速度表-7垂向货位横向加速度a0y(m/s2)纵向加速度a0x(m/s2)上甲板高位7.16.96.86.76.76.86.97.17.43.8上甲板低位6.56.36.16.16

5、.16.16.36.56.72.9二层舱5.95.65.55.45.45.55.65.96.22.0底舱5.55.35.15.05.05.15.35.55.91.5纵向货位(距船尾)/L0.10.20.30.40.50.60.70.80.9垂向加速度a0z(m/s2)7.66.25.04.34.35.06.27.69.2与船长(L)和航速(V)有关的K1修正系数表F-8V(kn)L(m)506070809010012014016018020091.201.091.000.920.850.790.700.630.57

6、0.530.49121.341.221.121.030.960.900.790.720.650.600.56151.491.361.241.151.071.000.890.800.730.680.63181.641.491.371.271.181.100.980.890.820.760.71211.781.621.491.381.291.211.080.980.900.830.78241.931.761.621.501.401.311.171.070.980.910.85与B/GM有关的K2修正系数表-9B/GM7

7、89101112≥13上甲板高位1.561.401.271.191.111.051.00上甲板低位1.421.301.211.141.091.041.00二层舱1.261.191.141.091.061.031.00底舱1.151.121.091.061.041.021.00作为μ和α函数的f值(f=μsinα+cosα)表-10μα-30-20-1001020304050600.30.720.840.931.001.041.041.020.960.870.760.10.820.910.971.001.000.97

8、0.920.830.720.590.00.870.940.981.000.980.940.870.770.640.50