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时间:2021-02-24
《商务与经济统计习题答案(第8版,中文版)SBE8-SM20.doc》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、Chapter20StatisticalMethodsforQualityControlLearningObjectives1.Learnabouttheimportanceofqualitycontrolandhowstatisticalmethodscanassistinthequalitycontrolprocess.2.Learnaboutacceptancesamplingprocedures.3.Knowthedifferencebetweenconsumer’sriskandproducer’srisk.4.Beabletousethebinomialprobabilitydis
2、tributiontodevelopacceptancesamplingplans.5.Knowwhatismeantbymultiplesamplingplans.6.Beabletoconstructqualitycontrolchartsandunderstandhowtheyareusedforstatisticalprocesscontrol.7.Knowthedefinitionsofthefollowingterms:producer'sriskassignablecausesconsumer'sriskcommoncausesacceptancesamplingcontrolc
3、hartsacceptablecriterionuppercontrollimitoperatingcharacteristiccurvelowercontrollimit13-1StatisticalMethodsforQualityControlSolutions:1.a.Forn=4UCL=m+3(s/)=12.5+3(.8/)=13.7LCL=m-3(s/)=12.5-3(.8/)=11.3b.Forn=8UCL=m+3(.8/)=13.35LCL=m-3(.8/)=11.65Forn=16UCL=m+3(.8/)=13.10LCL=m-3(.8/)=11.90c.UCLandLCLb
4、ecomeclosertogetherasnincreases.Iftheprocessisincontrol,thelargersamplesshouldhavelessvarianceandshouldfallcloserto12.5.2.a.b.UCL=m+3(s/)=5.42+3(.5/)=6.09LCL=m-3(s/)=5.42-3(.5/)=4.753.a.b.c.UCL=p+3=0.0540+3(0.0226)=0.1218LCL=p-3=0.0540-3(0.0226)=-0.0138UseLCL=04.RChart:UCL==1.6(1.864)=2.98LCL==1.6(0
5、.136)=0.22Chart:UCL==28.5+0.373(1.6)=29.10LCL==28.5-0.373(1.6)=27.905.a.UCL=m+3(s/)=128.5+3(.4/)=128.99LCL=m-3(s/)=128.5-3(.4/)=128.0120-13StatisticalMethodsforQualityControlb.incontrolc.outofcontrol6.ProcessMean=UCL=m+3(s/)=20.01+3(s/)=20.12Solvefors:7.SampleNumberObservationsRi131422833.6714226183
6、526.3317325303429.679417252121.008538293534.009641423639.676721172922.3312832262828.676941343336.0081029173025.33131126314032.33141223192522.3361317243224.33151443351731.67261518252924.00111630423134.33121728363232.0081840293133.33111918292825.00112022342627.3312=11.4andRChart:UCL==11.4(2.575)=29.35
7、LCL==11.4(0)=0Chart:UCL==29.17+1.023(11.4)=40.8LCL==29.17-1.023(11.4)=17.520-13StatisticalMethodsforQualityControlRChart:Chart:8.a.b.UCL=p+3=0.0470+3(0.0173)=0.0989LCL=p-3=0.0470-3(0.0173)=-0.004920-1
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