商务与经济统计习题答案（第8版，中文版）SBE8-SM19.doc

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1、NonparametricMethodsChapter19NonparametricMethodsLearningObjectives1.Learnthedifferencebetweenparametricandnonparametricmethods.2.Knowtheparticularadvantagesofnonparametricmethodsandwhentheyareandwhentheyarenotapplicable.3.Learnhowtousethesigntestfortheanalysisofpairedcomparisons.4.

2、Beabletousethesigntesttoconducthypothesistestsaboutamedian.5.BeabletousetheWilcoxonsigned-ranktestandtheMann-Whitney-Wilcoxontesttodeterminewhetherornottwopopulationshavethesamedistribution.6.BeabletousetheKruskal-Wallistestsforthecomparisonofkpopulations.7.BeabletocomputetheSpearma

3、nrankcorrelationcoefficientandtestforasignificantcorrelationbetweentwosetsofrankings.19-21NonparametricMethodsSolutions:1.BinomialProbabilitiesforn=10,p=.50.xProbabilityxProbability0.00106.20511.00987.11722.04398.04393.11729.00984.205110.00105.2461P(0)+P(1)=.0108;addingP(2),exceeds.

4、025requiredinthetail.Therefore,rejectH0ifthenumberofplussignsislessthan2orgreaterthan8.Numberofplussignsis7.DonotrejectH0;concludethatthereisnoindicationthatadifferenceexists.2.Therearen=27casesinwhichavaluedifferentfrom150isobtained.Usethenormalapproximationwithµ=np=.5(27)=13.5andU

5、sex=22asthenumberofplussignsandobtainthefollowingteststatistic:Witha=.01,werejectifz>2.33;sincez=3.27>2.33werejectH0.Conclusion:themedianisgreaterthan150.3.a.Letp=probabilitythesharesheldwillbeworthmoreafterthesplitH0:p£.50Ha:p>.50IfH0cannotberejected,thereisnoevidencetoconcludestoc

6、ksplitscontinuetoaddvaluetostockholdings.b.Letxbethenumberofplussigns(increasesinvalue).Usethebinomialprobabilitytableswithn=18(therewere2tiesinthe20cases)P(x>12)=.0482RejectH0ifthenumberof+signsisgreaterthan12.c.Withx=14,werejectH0.Theresultssupporttheconclusionthatstocksplitsarebe

7、neficialforshareholders.19-21NonparametricMethods4.Weneedtodeterminethenumberwhosaidbetterandthenumberwhosaidworse.Thesumofthetwoisthesamplesizeusedforthestudy.n=.34(1253)+.29(1253)=789.4Usethelargesampletestusingthenormaldistribution.Thismeansthevalueofn(n=789.4above)neednotbeinteg

8、er.Hence,µ=.5n=.5(7